Today's Question - Magic was killing some time shuffling cards (after the close, of course). He peeled out a "club" set (2, 3, 4, 5, 6, 7, 8, 9, ace). He laid out these cards in a set 3 x 3 so that each row horizontally or vertically added up to "15". (Hint: the ace is a "1".) Can you match Magic's magic?

Reveal Answer Corner Answer - Magic's 3 x 3 cube could be filled in as follows in the rows across: First row - 8, 1, 6; second row - 3, 5, 7; third row - 4, 9, 2. Thus each row up or down would equal 15 (and as Peter Bradford points out - so would the diagonals.)

Doesn't match      Missing info      Like question